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বাং

Mean, median and mode: drag the points, watch the markers move

The mean, median and mode are three different ways to summarize a set of numbers with one representative value; the range and the standard deviation describe how spread out they are. In the example below, 7 values have a mean of 6 and a median of 5.

Drag a dot to change it, or use the sliders

Mean, x̄MedianModeMean ± 1 standard deviation

Controls

Data type

2
4
5
5
7
9
10

Readings

Mean, x̄
6.00
Median
5.00
Mode
5
Range (highest − lowest)
8
Standard deviation, σ
2.62

How to use this simulation

  1. In raw-data mode, drag any dot on the number line: the mean, median and mode markers update instantly.
  2. Tick "Add an outlier value": the mean marker jumps a long way, while the median marker barely shifts.
  3. Watch the shaded band: it shows the mean ± 1 standard deviation, and it widens as the data spreads out more.
  4. Switch to grouped-data mode and slide each class interval's frequency: watch the median class and modal class change.
  5. Set one class frequency to zero: its histogram bar disappears, and the median and mode both shift toward the surviving classes.

A class test and a very large salary

Seven friends score 2, 4, 5, 5, 7, 9, 10 out of 10 on a class test. If someone asks "how did your group do", and you can only answer with one number, what do you say? Finding that one representative number, in three different ways, is what this page is about.

Now imagine a small office where nine employees earn roughly the same modest salary, and a tenth person — the owner — earns many times more than everyone else. Report the “average salary” and you get a number nobody in the office is actually close to. Report the “median salary” instead, and that one very large number barely moves it. That gap is one of the most useful lessons in statistics.

The simulation above shows exactly this: dots sit on a number line, and ticking the outlier switch adds one far-away value, just like that office owner's salary.

Starting from zero: central tendency and spread

Summarizing a set of numbers with one typical value is called a measure of central tendency. There are three common ones: the mean, the median and the mode.

The mean is every value added up and divided by how many there are: x̄ = (Σx) ÷ n. The median is the middle value once the data is sorted from smallest to largest (the average of the two middle values if there is an even number of them). The mode is whichever value occurs most often.

Two groups can share the same mean and still be spread out very differently. That is measured separately, by a measure of dispersion: the simplest is the range (highest minus lowest), and a more careful one is the standard deviation, which averages how far every value sits from the mean.

Key terms

Get the vocabulary straight before the formulas; definition questions come straight from this table.

TermSymbolWhat it means
Meanx̄The sum of every value, divided by how many values there are
MedianMedianThe middle value once the data is sorted from smallest to largest
ModeModeThe value that occurs most often in the data
RangeRangeThe highest value minus the lowest value
Standard deviationσThe square root of the average squared distance from the mean
Outlier—A value that sits unusually far from the rest of the data
Class widthhThe width of one class interval in grouped data (upper limit minus lower limit)
Median class—The class where the running total of frequencies first passes n/2

The mean, median and mode formulas

Each formula follows directly from its definition.

x̄ = (Σx) / nSum every value, divide by how many there are

Median = the ((n+1)/2)th value, if n is oddIf n is even, average the two middle values

σ = √( Σ(x − x̄)² / n )Average the squared distance from the mean, then take the square root

Finding the median: odd n versus even n

Sort the data from smallest to largest first. If the number of values, n, is odd, the single middle value is the median. If n is even, there are two middle values, and the median is their average.

In the example (7 values, odd): sorted, 2, 4, 5, 5, 7, 9, 10. The middle (4th) value is 5, so the median is 5.

Why the standard deviation squares first, then takes a square root

Simply averaging how far each value sits from the mean (x − x̄) always gives zero, because the positive distances of values above the mean cancel the negative distances of values below it. Squaring each distance fixes that (every squared number is positive), and taking the square root at the end brings the units back to normal, after averaging the squares.

In the example, the mean is 6. Each value's deviation and its square are shown in the table below; the average of those squares is 6.86, and its square root, σ, is 2.62.

Why the median resists an outlier

Calculating the mean needs the exact magnitude of every value, so one unusually large or small value pulls the mean toward itself. Calculating the median only needs the order of the values — where each one sits once they are sorted — not how large it is. An outlier sits at one end of the sorted list, but the position in the middle barely moves.

In the example (7 values): mean 6, median 5. Adding one outlier of 35 (now 8 values): the mean jumps to 9.625 — a huge change. But the median becomes just 6 — barely different, because it is still the average of the two middle values, and those two values barely changed.

That is exactly why real-world reports often use "median" instead of "mean" wherever extreme values are common, such as income or house prices: a country's "median income" is reported precisely because a handful of extremely wealthy people would drag the mean far above what a typical person earns.

Grouped data: summarizing a long list

With hundreds of individual values, writing each one down is impractical. Instead, the values are split into equal-width class intervals (say, 0–5, 5–10, 10–15, …) and only the count in each class — the frequency — is recorded. That summary is called grouped data.

Grouped data no longer records each exact value, only which class it fell into, so the formulas make one assumption: every value in a class is treated as sitting at that class's midpoint. That gives the mean formula its shape, while the median and mode use an interpolation formula instead, which assumes the values are spread evenly across the class.

x̄ = Σ(f × midpoint) / ΣfEvery value is assumed to sit at its class midpoint

Median = L + ((n/2 − cf)/f) × hL = lower limit of the median class, cf = cumulative frequency before it

Mode = L + ((f₁ − f₀)/(2f₁ − f₀ − f₂)) × hL = lower limit of the modal class, f₁ its frequency, f₀ and f₂ the neighbours

Checking the simulation's default grouped data

The default frequencies are 4, 8, 10, 6, 2 for classes 0–5, 5–10, 10–15, 15–20, 20–25, a total of n = 30. The mean is 11.5. The median class is 10–15 (the running total 4+8 = 12 first passes n/2 = 15 once 10 is added, reaching 22), giving a median of 11.5. That same class also has the highest frequency (10), so it is the modal class too, giving a mode of 11.67.

Which measure to use, and when

All three measures are correct, but they are not equally useful in every situation.

SituationBest measureWhy
Data is fairly evenly spread, with no extreme valuesMeanUses every value, so it carries the most information
Some extreme values or outliers exist (income, wealth, house prices)MedianDepends only on position, not magnitude, so outliers cannot pull it
Data is not numeric, but categorical (colour, shoe size, favourite team)ModeThe only measure that still makes sense for non-numeric data
Exact values are unavailable, only class frequencies areGrouped formulasInterpolation gives an approximate median and mode

Try these in the simulation

Predict the outcome before you run the simulation, then check.

  • In raw-data mode, drag two dots onto the exact same value: the mode readout locks onto that value, and the dots visibly stack on the number line.
  • Spread every dot to a different value, with no repeats at all: the mode readout reports that no value repeats.
  • Turn the outlier on and watch the shaded band (mean ± 1 SD): it widens a lot once the outlier is added, because the spread has grown.
  • In grouped mode, push one middle class's frequency to the maximum: that class becomes the modal class, and the median class often lands there too.
  • In grouped mode, set the first and last class frequencies to zero: the remaining three classes still give a valid median and mode, using the exact same formulas.

Solved problems

Every solution sorts the data first, then states the formula, then substitutes — write it the same way in an exam.

Problem 1: the simulation's default raw data

Data: 2, 4, 5, 5, 7, 9, 10 (n = 7). Mean = (2+4+5+5+7+9+10)/7 = 6. The middle value in the sorted list is 5, so the median is 5. The value 5 occurs twice while every other value occurs once, so the mode is 5. The range is 10 − 2 = 8.

Problem 2: what an outlier changes

Adding 35 to problem 1's data (n = 8): the new mean is (42+35)/8 = 9.625, a huge jump from 6. But the new median is only 6, barely different from 5, because the two middle values hardly moved.

Problem 3: the simulation's default grouped data

Classes 0–5, 5–10, 10–15, 15–20, 20–25 with frequencies 4, 8, 10, 6, 2 (n = 30). Mean = Σ(f×midpoint)/n = 11.5. The median class is 10–15 (L=10, cf=12, f=10, h=5): Median = 10 + ((15−12)/10)×5 = 11.5. The modal class is also 10–15 (f₁=10, f₀=8, f₂=6): Mode = 10 + ((10−8)/(20−8−6))×5 = 11.67.

Problem 4: when there is no mode

Five students score 45, 50, 55, 60, 65 — every value is different. Mean = (45+50+55+60+65)/5 = 55. Median (the middle value) = 55. But no value repeats, so there is no mode here — that is a valid outcome, not an error.

Problem 5: when there are two modes

Seven shoe sizes: 6, 7, 7, 8, 9, 9, 10. Mean = 8, median (the 4th value) = 8. Both 7 and 9 occur twice while every other size occurs once, so there are two modes: 7 and 9.

Problem 6: a fresh grouped-data example

30 students' marks are grouped into classes 0–10, 10–20, 20–30, 30–40, 40–50 with frequencies 3, 7, 10, 6, 4 (n = 30). Mean = 25.33. The median class is 20–30 (L=20, cf=10, f=10, h=10): Median = 20 + ((15−10)/10)×10 = 25. The modal class is also 20–30 (f₁=10, f₀=7, f₂=6): Mode = 20 + ((10−7)/(20−7−6))×10 = 24.29.

Problem 7: the same mean, different spread

Group A: 5, 5, 5, 5, 5. Mean = 5, standard deviation = 0, since no value differs from the mean at all. Group B: 1, 3, 5, 7, 9. The mean is also 5 — identical! But the standard deviation is 2.828, because the values are spread widely around that same mean. Judging the two groups by their mean alone would miss this completely.

Quick reference: the standard deviation, step by step

For problem 1's data, here is every value's deviation from the mean and its square. Averaging the squares and taking the square root gives σ.

Value, xx − mean(x − mean)²
2-416
4-24
5-11
5-11
711
939
10416

Mistakes almost everyone makes

Avoiding these keeps exam marks from slipping away on mean, median and mode questions.

  • Forgetting to sort the data before finding the median — the definition of median depends entirely on the sorted order.
  • Taking only one middle value when n is even, instead of averaging the two middle values.
  • Thinking the mode is the largest value — the mode is the most frequent value, not the biggest one.
  • Using n instead of n/2 in the grouped median formula — the formula needs half the total frequency.
  • Averaging the deviations directly in a standard deviation calculation, without squaring first — that always gives zero, because positive and negative deviations cancel.
  • Calling the mean "wrong" just because one outlier changed it a lot — the mean is not wrong, only sensitive to outliers, which is exactly why the median is more trustworthy for that kind of data.

Mean, median and mode in real life

These measures show up in newspapers and reports well outside the exam hall.

  • A country reports its "median income", not its "average (mean) income", because a small number of extremely wealthy people would drag the mean far above what a typical person earns.
  • A shoe shop tracks its best-selling size (the mode) so it can keep more stock of that size on the shelf.
  • Exam results are analysed using both the class mean and the class median; a big gap between them signals that some students scored unusually high or low.
  • A weather forecast reporting a month's average temperature also needs its spread, since two months can share the same mean temperature while one stays steady and the other swings wildly.
  • Factories aim for a low standard deviation in manufactured part sizes, since a small standard deviation means most parts come out close to the target size.

Exam tips

Mean, median and mode questions appear on almost every statistics syllabus. Two habits earn marks reliably: always sort the data before finding the median, and always check whether n is odd or even before picking the median rule.

A worked exam-style question

Question: Ten farmers in a village own 2, 4, 5, 5, 7, 9, 10 acres of land, and one large landowner owns 35 acres. (a) Define median. (b) Find the mean land held by the first seven farmers. (c) Find the mean and median for all eight landowners. (d) Is it fair to say that the large landowner makes the mean misleading, and the median more trustworthy? Justify your answer.

(c): Mean = 9.625, median = 6. (d): the mean jumped hugely from 6 to 9.625, while the median moved only slightly from 5 to 6, so the statement is justified.

Revision: one-screen summary

The night before an exam, this list and the tables above are enough to refresh everything.

  • Mean x̄ = (Σx)/n — uses every value, sensitive to outliers.
  • Median = the middle value of sorted data — depends on position, resistant to outliers.
  • Mode = the most frequent value — none if nothing repeats, more than one if there is a tie.
  • Range = highest − lowest; standard deviation σ = √(Σ(x−x̄)²/n).
  • Grouped data finds the mean from midpoints, and the median and mode from an interpolation formula.
  • When outliers are present, the median is the more trustworthy representative value.

Frequently asked questions

What's the difference between mean, median and mode?

The mean is the sum of every value divided by how many there are; the median is the middle value of the sorted data; the mode is the value that occurs most often. All three summarize where data is centred, but they are calculated differently.

How do I find the median?

Sort the data from smallest to largest. If n is odd, the middle ((n+1)/2)th value is the median. If n is even, average the two middle values. In the example, the middle of 7 sorted values is 5, so the median is 5.

What is the formula for the median and mode of grouped data?

Median = L + ((n/2 − cf)/f) × h, where L is the lower limit of the median class, cf is the cumulative frequency before it, f is its frequency, and h is the class width. Mode = L + ((f₁−f₀)/(2f₁−f₀−f₂)) × h, where f₁ is the modal class frequency and f₀, f₂ are the neighbouring classes' frequencies.

Should I use the mean or the median when there is an outlier?

The median is the safer choice when an outlier is present, because it depends only on position, not magnitude. In the example, adding an outlier of 35 jumps the mean from 6 to 9.625, while the median barely changes.

Can a dataset have no mode?

Yes. If every value in the data is different, with none repeated, there is no mode. That is a normal, valid outcome, not a mistake.

Can a dataset have more than one mode?

Yes. If two or more values are tied for the highest frequency, all of them are modes. Such data is called bimodal (two modes) or multimodal (more than two).

What does the standard deviation tell you?

The standard deviation measures how spread out the data is around the mean. A small standard deviation means the values cluster close to the mean; a large one means they are spread widely, even if two datasets share the exact same mean.

Why isn't the mean always a reliable summary?

Because the mean is calculated from the exact magnitude of every value, one unusually large or small value (an outlier) can pull it a long way from where most of the data actually sits — like one very wealthy person raising a group's average income far above what is typical.

What's the difference between range and standard deviation?

The range is just the highest value minus the lowest — it depends on only two values. The standard deviation considers how far every value sits from the mean, making it a more reliable measure of spread.

Why does the grouped-data mean formula use class midpoints?

Grouped data records only which class each value fell into, not the exact value. Assuming every value sits at its class midpoint gives a reasonable approximate mean without needing the original individual values.

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