Drag charges · double-click to remove · hover to probe E
Controls
Charge arrangement
Sign of charge
Readings
- Field at probe, E
- 4.46 × 10⁶N/C
- Direction of E (from +x)
- 50°
- Potential at probe, V
- 2.32 × 10⁵V
- Distance to nearest charge, r
- 6.4cm
- Force on test charge, F
- 4.46 × 10⁻³N
- Net charge
- 0.0µC
How to use this simulation
- Pick an arrangement: a single charge, a dipole, two like charges or four charges.
- Drag any charge and the field lines are redrawn instantly. Double-click a charge to remove it.
- Click a charge to select it, then change its size with the slider: the number of lines changes with it.
- Hover or touch anywhere: the field strength, its direction and the potential V at that point appear in the readings panel.
- Press ▶ to release the orange +1 nC test charge and watch where the field pushes it.
Why does a balloon stick to the wall?
Rub a balloon on your hair a few times and hold it near your head: your hair stands up and reaches for it. Put it against a wall and it just stays there. Nothing is glued, nothing is touching your hair, and yet there is clearly a force.
The small shock you get from a door handle after walking on carpet, the crackle when you pull off a wool jumper in winter, and a lightning bolt splitting a stormy sky are all the same story at different sizes. In each case, electric charge has built up somewhere and is pulling or pushing on other charges.
Behind every one of these is an invisible zone of influence around the charge: the electric field. This page makes that invisible thing visible, then shows step by step how physicists measure it.
Starting from zero: charge and field
Everything is made of atoms, and atoms contain positive protons and negative electrons. Normally the two balance, so objects are neutral. Rubbing a balloon on hair moves a few electrons from your hair to the balloon: the balloon becomes negatively charged and your hair positively charged. Charge is measured in coulombs (C).
Now think about gravity. The Earth pulls you down without touching you, because it is surrounded by a gravitational field. A magnet grabs a paper clip from a distance because it has a magnetic field. In the same way, every charge changes the space around it, and any other charge that wanders into that space feels a force.
That region of influence is the electric field. A friendly picture: when a loud speaker is playing, you can hear it anywhere in the room, loudest right next to it and fainter by the door. The electric field is like that, strong near the charge and weaker far away.
There is only one rule for how charges treat each other: like charges repel, unlike charges attract. Two positives push apart; a positive and a negative pull together.
Words you will keep meeting
Here are the key terms in one place, so nothing trips you up later:
| Term | What it means in plain words | Symbol and unit |
|---|---|---|
| Charge | The property of matter that makes it feel and exert electric forces | q, coulomb (C) |
| Coulomb | The SI unit of charge; one electron carries only 1.6 × 10⁻¹⁹ C | C |
| Test charge | A tiny positive charge used to probe a field without disturbing it | q₀ |
| Electric field intensity | The force on a unit positive charge placed at a point | E, N C⁻¹ or V m⁻¹ |
| Field line | An imaginary line whose tangent at any point shows the direction of E | — |
| Electric potential | Work done to bring a unit positive charge from infinity to that point | V, volt (V) |
| Permittivity | How much a medium weakens electric forces; in vacuum it is ε₀ | ε₀ = 8.85 × 10⁻¹² C² N⁻¹ m⁻² |
From Coulomb's law to field intensity
To put a number on the field, you first need the force between two charges. That is exactly what Coulomb's law gives.
Coulomb's law
The force between two point charges is proportional to the product of the charges and inversely proportional to the square of the distance between them. It acts along the straight line joining them.
"Inverse square" is the important bit: double the distance and the force drops to a quarter; triple it and the force drops to a ninth. Step back just a little and the force falls off quickly.
F = k·q₁q₂ / r²Coulomb's law
k = 1/(4πε₀) ≈ 9 × 10⁹ N m² C⁻²Coulomb's constant in vacuum
Defining the field intensity
Place a tiny positive test charge q₀ at a point in the field. Measure the force F on it and divide by q₀. The result is the electric field intensity at that point. Why divide? So the answer describes the field itself, not the size of whatever probe you happened to use.
E = F / q₀definition
E = k·q / r²field of a point charge q at distance r
Finding the direction
Field intensity is a vector: it has a size and a direction. The easy trick is to imagine a positive test charge sitting at the point. Whichever way it gets pushed is the direction of E.
- Around a positive charge, E points outward, away from the charge.
- Around a negative charge, E points inward, towards the charge.
- A negative charge (an electron, say) placed in a field is pushed opposite to E.
More than one charge: superposition
With several charges, work out E from each one separately, then add them as vectors. Same direction: add. Opposite directions: subtract. At an angle: use vector addition.
E⃗ = E⃗₁ + E⃗₂ + E⃗₃ + …principle of superposition
The unit of electric field
From E = F/q₀ the unit is newton per coulomb (N C⁻¹). Worked out another way, the same quantity comes out in volt per metre (V m⁻¹). They are identical: 1 N C⁻¹ = 1 V m⁻¹, and either is correct in an exam.
Field lines: a picture of the invisible
You cannot see a field, so Michael Faraday came up with a brilliant trick: draw imaginary lines so that the tangent at any point shows the direction of E there. These are electric field lines, and the lines drifting in the simulation above are calculated exactly this way.
Rather than memorising the properties, learn why each one is true. Then you will never forget them:
- Field lines start on positive charges and end on negative charges, because a positive test charge moves away from positive and towards negative.
- Two field lines never cross. If they did, the crossing point would have two tangents, meaning two directions of E at one point, which is impossible.
- Where lines are crowded the field is strong; where they spread out it is weak. That is why lines bunch up near a charge and thin out far away.
- Field lines meet a conductor's surface at right angles. A slanted line would have a component along the surface, and charges would slide around.
- Field lines from static charges never form closed loops. This is a big difference from magnetic field lines.
- A bigger charge has more lines leaving or entering it.
A single charge
A lone positive charge sends lines straight out in every direction, like the spokes of a bicycle wheel. A negative charge has the same pattern with the arrows pointing in.
A dipole
Put equal and opposite charges side by side and the lines curve out of the positive one and bend round into the negative one, like a set of stretched arches. The lines are densest in the gap between them.
Two like charges
Two positive charges seem to push each other's lines away. Exactly halfway between two equal charges the two fields cancel. That is a neutral point, where E = 0.
Is electric field the same as electric potential?
No, and examiners love this question. Field intensity tells you how hard, and in which direction, a unit charge gets pushed. Potential tells you how much work it takes to bring a unit charge there. Think of a hill: the potential is the height of a spot, the field is how steep the slope is.
| Feature | Field intensity (E) | Potential (V) |
|---|---|---|
| Type of quantity | Vector: has direction | Scalar: no direction |
| Point-charge formula | E = kq/r² | V = kq/r |
| Falls off as | 1/r² | 1/r |
| Unit | N C⁻¹ or V m⁻¹ | J C⁻¹, i.e. volt (V) |
| With several charges | Vector addition | Ordinary addition |
| Midpoint of a dipole | Not zero | Zero |
Try it yourself in the simulation
When you finish reading, go back up and try these one by one. Each one proves a textbook rule in front of your eyes.
- Choose "Single positive" and move the pointer from near the charge to far away. Watch E fall in the readings panel. Does doubling the distance cut it to about a quarter?
- Choose "Dipole (+ and −)" and hover exactly halfway between the charges. E is not zero, and it points from + to −.
- Choose "Two like charges" and hunt for the middle. Somewhere E drops almost to zero: that is the neutral point.
- Click a charge and raise its size. More field lines leave it.
- Press ▶ and watch the orange test charge speed up as it heads towards the negative charge.
Solved problems, step by step
All of these use k = 9 × 10⁹ N m² C⁻². Always convert to SI units first: multiply µC by 10⁻⁶ to get coulombs and turn cm into m. Most wrong answers come from skipping this.
Problem 1: force between two charges
Charges of 3 µC and −4 µC are 0.2 m apart. Find the force and say whether it is attractive or repulsive.
Solution: F = k·q₁q₂/r² = 9 × 10⁹ × (3 × 10⁻⁶) × (4 × 10⁻⁶) / 0.04 = 2.70 N. The charges are opposite, so the force is attractive.
Problem 2: field and potential of a point charge
Find the field intensity and the potential 0.3 m from a 2 µC charge. What force acts on a 1 nC test charge placed there?
Solution: E = kq/r² = 9 × 10⁹ × 2 × 10⁻⁶ / 0.09 = 2.00 × 10⁵ N C⁻¹, pointing away from the charge. V = kq/r = 6.00 × 10⁴ V. Force F = q₀E = 2.00 × 10⁻⁴ N.
Problem 3: doubling the distance
At 0.6 m from the same charge, E = 5.00 × 10⁴ N C⁻¹, which is 4 times smaller. Because E ∝ 1/r², doubling the distance divides the field by four. Check it with the probe in the simulation.
Problem 4: the midpoint of a dipole
Charges of +2 µC and −2 µC are 0.2 m apart. Find the field at the midpoint.
Solution: the midpoint is 0.1 m from each charge. Each one gives E = 9 × 10⁹ × 2 × 10⁻⁶ / (0.1)² = 1.80 × 10⁶ N C⁻¹. The positive charge's field points away from it, towards the negative charge; the negative charge's field also points towards itself. Both point the same way, so they add: E = 3.60 × 10⁶ N C⁻¹, towards the negative charge.
If both charges were +2 µC, the two fields at the midpoint would be equal and opposite, so E = 0. That is the neutral point.
Problem 5: an electron in a field
An electron sits in a uniform field of 1 × 10⁴ N C⁻¹. Find the force on it and its acceleration (e = 1.6 × 10⁻¹⁹ C, mₑ = 9.11 × 10⁻³¹ kg).
Solution: F = eE = 1.6 × 10⁻¹⁵ N. Acceleration a = F/m = 1.76 × 10¹⁵ m s⁻². Electrons are so light that even a modest field gives them an enormous acceleration. The force points opposite to the field, because the electron is negative.
Mistakes almost everyone makes
These turn up in exam scripts again and again, so spot them now:
- Plugging in µC without converting to C, which makes the answer a million times too big.
- Forgetting to square r, or squaring it in the potential formula where it should not be.
- Adding the fields of several charges as plain numbers and ignoring direction. E is a vector; potential is a scalar.
- Drawing the force on an electron in the same direction as E.
- Treating a field line as the path a test charge must follow. Field lines show the force, not the velocity.
Electric fields in real life
The electric field is not just a textbook idea. It is at work all around you:
- Lightning conductors: a pointed metal rod on top of a tall building, connected to the ground by a thick wire, gives a lightning strike an easy path to earth instead of through the walls.
- Photocopiers and laser printers: light arranges charge on a drum in the shape of the page, and powdered toner sticks only where the charge is.
- Electrostatic precipitators: factory chimneys charge the dust in smoke and then pull it onto oppositely charged plates, so far less dust escapes into the air.
- Safety in a car: during a thunderstorm you are relatively safe inside a car with a metal roof, because the charge travels over the outer metal shell. This is a Faraday cage.
- Spray painting: paint droplets are charged so they are pulled evenly onto the metal body of a car, wasting less paint.
Exam corner
Questions on this topic tend to come in a few familiar shapes. Here is what examiners usually ask, with the core of a good answer.
Definitions
Define electric field intensity. Answer: the force experienced by a unit positive charge placed at that point in the field; it is a vector, E = F/q₀, measured in N C⁻¹.
Explain why
Why do field lines never intersect? Answer: at a crossing point there would be two tangents, giving two directions of E at one point, which is impossible.
Why is the field not the same everywhere around a charge? Answer: E = kq/r², so it falls with the square of the distance.
Calculations
Expect two charges and a distance. You may be asked for the force between them, the field at a point such as the midpoint, or where the field is zero. Use superposition and show directions clearly, as in problems 1 and 4 above.
The whole topic at a glance
If you only have five minutes before an exam, read this:
- Electric field: the region around a charge where another charge feels a force.
- Coulomb's law: F = kq₁q₂/r², with k ≈ 9 × 10⁹ N m² C⁻².
- Field intensity: E = F/q₀ = kq/r², a vector, unit N C⁻¹ = V m⁻¹.
- Potential: V = kq/r, a scalar, unit volt.
- Field lines run from + to −, never cross, and are crowded where the field is strong.
- For several charges: add fields as vectors, add potentials as numbers.
Frequently asked questions
What is an electric field?
An electric field is the region around a charge in which another charge experiences a force of attraction or repulsion.
What is the formula for electric field?
Field intensity is E = F/q₀, the force per unit positive test charge. For a point charge q at distance r in vacuum, E = kq/r², with k ≈ 9 × 10⁹ N m² C⁻².
What is the SI unit of electric field?
Newton per coulomb (N C⁻¹), which is exactly equal to volt per metre (V m⁻¹).
Why don't electric field lines cross?
At a crossing point there would be two tangents and therefore two directions of the field at one point. The field has only one direction at any point, so lines cannot cross.
How is electric field different from electric potential?
Field is a vector giving the force per unit charge, and falls as 1/r² for a point charge. Potential is a scalar giving the work per unit charge, and falls as 1/r.
What is a neutral point in an electric field?
A point where the fields of several charges cancel out, so the resultant field is zero. The midpoint between two equal like charges is an example.
Is electric field a vector or a scalar?
A vector. It has both size and direction: away from positive charges and towards negative ones.
Keep studying this topic
The animation made the idea click; now turn it into marks. Syllabus, suggestions, textbooks and admission-test guides are below.
SSC
SSC Physics: syllabus and preparation
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HSC Physics: syllabus and preparation
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Dhaka University science unit admission 2026-27
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প্রতিবেদন: বিজ্ঞান মেলা (in Bangla)
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Paragraph: Science in Everyday Life
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SSC
SSC syllabus
HSC
HSC syllabus
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