The signal only travels down the axon once the stimulus clears the threshold — the all-or-none law.
Controls
Readings
- Membrane potential, V
- -70.0mV
- Membrane phase
- Resting
- Conduction speed
- 60.0m/s
- Time to reach the terminal
- 16.7ms
- Signal progress
- 0%
- Threshold needed
- 15mV
- Signal status
- Not fired
How to use this simulation
- Drag stimulus down to 10 mV, below threshold, and press play: the potential nudges up and settles back — no signal ever leaves the cell body.
- Set stimulus to 20 mV, above threshold, and play again: the graph on the right shows a full spike from −70 to +30 mV, and the signal then races down the axon.
- Turn the myelin sheath off: the signal now advances continuously along the whole axon instead of hopping node to node, and the conduction speed reading drops sharply.
- Turn myelin back on and drag the diameter slider: watch the conduction speed and the time-to-terminal reading change together.
- Once the signal reaches the terminal, watch the synapse: vesicles release neurotransmitter that crosses the cleft and reaches the receptors on the next neuron.
How your hand moves before you even feel the burn
Touch a hot pan and your hand is already pulling back before the pain even registers. The whole round trip — skin to spinal cord, spinal cord back to muscle — happens in a few milliseconds. How does one message cross that whole distance so fast?
The answer is built into the neuron's own membrane. It is not a passive wrapper; it can generate and carry an electrical signal itself. That signal is the nerve impulse, or action potential, and this simulation lets you fire one yourself and watch it race down an axon.
A vivid real fact: pufferfish toxin (tetrodotoxin) works by jamming exactly this signal — it blocks Na⁺ channels, so depolarisation can never start, muscles never receive the message, and paralysis follows. A dentist's local anaesthetic uses the very same trick, just safely and temporarily.
Starting from zero: the structure of a neuron
A neuron, the structural and functional unit of the nervous system, has four main parts. Dendrites are short branches off the cell body that receive messages from other neurons or from a sense organ. The cell body (soma) holds the nucleus and other organelles — it is the cell's life-support centre.
A single long projection, the axon, leaves the cell body and carries the signal away. Many axons are wrapped in fatty myelin, laid down by Schwann cells in the peripheral nervous system, with regular gaps called nodes of Ranvier where the myelin is absent. At the far end the axon branches into the axon terminal, which forms a synapse with the next cell.
Some human axons are only a few millimetres long (interneurons deep inside the brain); others run over a metre — a motor neuron from the spinal cord to a toe, for instance. The axon-length slider here spans that real range, 2 cm to 120 cm.
Key terms in nerve conduction
Get the vocabulary straight before the formulas; definition questions in exams come straight from this table.
| Term | What it means |
|---|---|
| Dendrite | A short branch that receives signals from other cells |
| Cell body (soma) | The cell's centre, holding the nucleus |
| Axon | The long fibre that carries the signal away |
| Myelin sheath | An insulating wrap around the axon that speeds up conduction |
| Node of Ranvier | A gap in the myelin where ion channels cluster |
| Resting potential | The membrane's voltage difference with no stimulus present |
| Threshold | The depolarisation level that must be reached to fire a spike |
| Action potential | The full, identical electrical spike triggered once threshold is crossed |
| Refractory period | The brief window after a spike when firing again is hard or impossible |
| Synapse | The junction where one neuron passes the signal to the next |
| Neurotransmitter | The chemical messenger released at a synapse |
The resting potential: why the inside is negative
Even with no stimulus at all, a neuron's membrane is not electrically neutral — the inside sits about -70 mV lower than the outside. Two things build this resting potential. First, the Na⁺–K⁺ pump spends ATP to push 3 Na⁺ out and 2 K⁺ in on every cycle, so Na⁺ piles up outside and K⁺ piles up inside.
Second, at rest the membrane is far more permeable to K⁺ than to Na⁺ (K⁺ leak channels stay open), so K⁺ drifts back out carrying positive charge with it, leaving the inside even more negative. The balance between these two settles at roughly −70 mV.
The pump runs continuously, but the fast rise and fall of an action potential is driven mainly by voltage-gated channels opening and closing — the pump's job is to keep restoring the underlying ion gradients over the longer term, not to generate the spike itself.
Threshold and the all-or-none law
A stimulus depolarises the membrane a little. If that depolarisation never reaches the threshold of -55 mV, the voltage-gated Na⁺ channels never open — the potential rises a little and drifts back to rest by itself. This is a local (graded) potential, and it does not travel.
Cross the threshold, though, and everything changes: a flood of Na⁺ channels opens and a full action potential fires, whatever the stimulus was beyond threshold — the peak is always about the same, +30 mV. This is the all-or-none law: the spike either fires completely, or not at all, with nothing in between.
So why does a harder pinch feel more painful, if every spike looks the same? Intensity is coded by how often spikes fire and how many fibres join in, not by how tall any one spike is. A stronger stimulus means a higher firing rate, not a bigger spike.
Stimulus needed = -55 − (-70) = 15 mVthreshold minus resting potential
The four named phases of an action potential
On the graph beside the simulation, this whole sequence takes only about two to three milliseconds. Here is each phase in turn.
Depolarisation
As soon as threshold is crossed, voltage-gated Na⁺ channels open. Since Na⁺ is far more concentrated outside, it rushes in down its gradient, and the potential rises from -70 to about +30 mV — a swing of roughly 100 mV. For a moment, the inside is actually positive relative to the outside.
Repolarisation
Around +30 mV the Na⁺ channels inactivate on their own, and the slightly slower voltage-gated K⁺ channels open. K⁺ rushes out, carrying positive charge with it, and the potential falls rapidly back towards negative values.
Hyperpolarisation
The K⁺ channels stay open a little longer than strictly needed, so the potential overshoots below rest, down to about -80 mV — roughly 10 mV past resting level. As the channels finally close, the potential eases back to rest.
The refractory period
While Na⁺ channels are still inactivated (through depolarisation and repolarisation), no new spike can fire however strong the stimulus — the absolute refractory period. During hyperpolarisation a new spike can fire, but only with a stronger-than-normal stimulus — the relative refractory period. This window sets the fastest rate at which a neuron can possibly fire.
Conduction: continuous versus saltatory
Once a patch of membrane fires, it depolarises the patch right next to it past threshold, so the wave keeps moving forward down the axon — in one direction only, because the patch just behind is still in its refractory period.
In an unmyelinated axon, ion channels are spread all along the membrane, so the signal advances step by step, continuously. In a myelinated axon, the myelin insulates the membrane so channels can only cluster at the nodes of Ranvier — the signal effectively hops from node to node, saltatory conduction, which is both faster and more energy-efficient (far less membrane needs active ion pumping).
Speed also depends on diameter. In a myelinated fibre, speed is roughly proportional to diameter — Hursh's rule: v ≈ 6 × d (m/s, with d in micrometres). In an unmyelinated fibre, speed grows only as the square root of diameter, so at the same diameter a myelinated fibre conducts far faster.
v_myelinated ≈ 6 × dd in micrometres, v in m/s — Hursh's rule
v_unmyelinated ≈ k × √da simple approximation for thin, unmyelinated fibres
time = length ÷ speedtime to reach the terminal
Try this in the simulation
Predict each outcome before you press play, then compare.
- Set stimulus to 5 mV: far below threshold, nothing travels, and the graph shows only a small bump that decays away.
- Set stimulus to exactly 15 mV: right at threshold, small changes either side flip the outcome completely — the all-or-none law in action.
- Fire the spike at 20 mV and again at 30 mV: the graph's peak stays the same both times, only the time to reach threshold shifts slightly — the potential itself never gets "bigger".
- Toggle myelin on and off at the same diameter and length, and compare the conduction speed and time-to-terminal readings.
- Drag the diameter slider from one end to the other and watch speed change linearly with myelin on, but only as the square root of diameter with it off.
Solved problems
Each solution states the formula first, then substitutes the numbers — write it the same way in an exam.
Problem 1: the simulation's own default fibre (d = 10 µm, length = 1 m, myelinated)
v = 6 × d = 6 × 10 = 60 m/s. Time to the terminal = length ÷ speed = 1/60 = 16.67 ms — exactly what the readings panel shows on load.
Problem 2: the same fibre with myelin switched off
v = k√d = 3.16 m/s, so time = 1/3.16 × 1000 = 316.2 ms. Myelin makes this fibre about 19.0 times faster — that is the real payoff of myelination.
Problem 3: a subthreshold stimulus of 10 mV
The local potential only reaches -70 + 10 = -60 mV, still below the -55 mV threshold. No action potential fires, and nothing travels down the axon.
Problem 4: the total voltage swing of one spike
From rest to peak the potential changes by 30 − (-70) = 100 mV. A swing this large is what reliably pushes the next patch of membrane past its own threshold.
Problem 5: doubling the diameter (myelinated, d = 1 µm vs d = 20 µm)
v₁ = 6 × 1 = 6 m/s, v₂ = 6 × 20 = 120 m/s. The ratio v₂/v₁ = 20 matches the diameter ratio exactly, because Hursh's rule is linear in d.
Problem 6: a short interneuron vs a long motor neuron, same fibre (2 cm vs 120 cm)
At the same speed 60 m/s: the short axon takes 0.33 ms, the long one 20 ms. The ratio 60 matches the length ratio exactly, since time = length ÷ speed is a straight proportion.
Problem 7: the depth of the after-hyperpolarisation
From rest at -70 mV down to the undershoot at -80 mV is a difference of 10 mV. Through this window, a stronger-than-usual stimulus is needed to fire again — the relative refractory period.
Problem 8: a one-synapse reflex arc, roughly
A 1 m sensory fibre at 60 m/s takes 16.67 ms to carry its signal. Add two synapses at about 0.5 ms delay each, and the whole reflex takes roughly 17.7 ms — fast enough to feel instantaneous, yet still a real, measurable time.
The synapse: from electrical signal to chemical message
An electrical signal cannot leap across to the next neuron on its own — a synaptic cleft, roughly 20 nanometres wide, sits in the way. So the message crosses in chemical form instead.
The steps run in order: the signal reaches the presynaptic terminal, voltage-gated Ca²⁺ channels open, Ca²⁺ flowing in triggers vesicles to fuse with the presynaptic membrane and release neurotransmitter (acetylcholine is the classic teaching example) into the cleft. The neurotransmitter diffuses across and binds receptors on the postsynaptic membrane, opening new channels there and creating a fresh change in potential in the next cell.
Finally, an enzyme breaks the neurotransmitter down, or the presynaptic cell reabsorbs it — otherwise the signal would just linger. Because only the presynaptic side has vesicles and only the postsynaptic side has receptors, a chemical synapse always passes the signal in one direction.
- The signal reaches the axon terminal
- Ca²⁺ channels open and Ca²⁺ enters
- Vesicles fuse and release neurotransmitter
- Neurotransmitter diffuses across the cleft
- It binds receptors and creates a new potential
- Enzymes or reuptake clear the neurotransmitter away
Common mistakes
Clearing these up is worth marks in every exam that touches this topic.
- Thinking a stronger stimulus makes a bigger spike. The peak is always the same (all-or-none); only the firing frequency changes.
- Picturing depolarisation as the membrane tearing open. Specific protein channels open and close; the membrane itself stays intact.
- Assuming saltatory conduction is the slow one. It is the fast, efficient one — continuous conduction along a bare axon is slower.
- Thinking nothing at all happens during the refractory period. Nothing can happen in the absolute part; a stronger stimulus can still fire a spike in the relative part.
- Assuming the electrical signal jumps straight across the synapse. Most synapses convert it into a chemical (neurotransmitter) message first.
Real life and medicine
One simple ion-movement principle explains most of the nervous system, and a good deal of medicine besides.
- Local anaesthetics (like a dentist's injection) briefly block Na⁺ channels, so pain signals never reach the brain.
- In multiple sclerosis, the immune system damages myelin, and conduction becomes slow and unreliable.
- A nerve conduction study measures exactly this conduction speed to diagnose nerve damage in a clinic.
- A knee-jerk reflex feels instant partly because the signal crosses only one synapse in the spinal cord and returns straight to the muscle, without a trip to the brain.
- The heart's own pacemaker cells and every skeletal-muscle contraction run on the very same Na⁺/K⁺-driven change in potential.
Exam corner
The neuron and the nerve impulse show up across school biology: structure and function questions on the neuron, definition and short-answer questions on threshold and the all-or-none law, and longer questions asking you to explain the resting-threshold-peak sequence with reasons.
A worked short-answer style question
Question: Explain why a myelinated axon conducts a nerve impulse faster than an unmyelinated one of the same diameter.
Model answer: In an unmyelinated axon, voltage-gated channels are spread continuously along the membrane, so the impulse must regenerate at every point, and speed grows only with the square root of diameter. In a myelinated axon, myelin insulates the membrane between the nodes of Ranvier, so channels cluster only at the nodes and the impulse jumps from node to node (saltatory conduction). This is both faster and cheaper in ATP, since far less membrane needs active pumping — in this simulation's own default fibre, myelin turns a 316.2 ms crossing into a 16.67 ms one, about 19.0 times faster.
Revision: the one-screen summary
This list plus the speed formulas above are all you need the night before an exam.
- Resting potential ≈ -70 mV, threshold ≈ -55 mV, peak ≈ +30 mV.
- Below threshold: only a local graded potential, no propagation. Above threshold: a full, identical action potential (all-or-none).
- Four phases: depolarisation (Na⁺ in) → repolarisation (K⁺ out) → hyperpolarisation (undershoot) → refractory period.
- Speed: myelinated v ≈ 6 × d (linear in diameter); unmyelinated v ∝ √d.
- Myelinated axons conduct by saltatory jumps between nodes of Ranvier; unmyelinated axons conduct continuously.
- At the synapse, the signal crosses as a one-way chemical message carried by neurotransmitter.
Frequently asked questions
What is a nerve impulse (action potential)?
A fast, identically shaped electrochemical change in a neuron's membrane, triggered once a stimulus crosses the -55 mV threshold, rising from about -70 mV to about +30 mV and travelling along the axon.
Why is the resting potential negative?
The Na⁺–K⁺ pump pushes Na⁺ out and K⁺ in, and the resting membrane leaks K⁺ back out more easily than Na⁺ in, leaving the inside at roughly -70 mV relative to the outside.
What is the all-or-none law?
Below threshold, no action potential fires at all; above threshold, a full action potential fires at its usual peak regardless of how far above threshold the stimulus was. There is no in-between spike.
What is saltatory conduction and why is it faster?
In a myelinated axon, ion channels cluster only at the nodes of Ranvier, so the signal effectively jumps from node to node; the insulated stretch in between is crossed almost instantly by electrotonic spread, making the whole trip far faster than continuous conduction.
Why does hyperpolarisation happen?
The voltage-gated K⁺ channels that repolarise the membrane stay open slightly longer than needed, so the potential briefly dips below resting level before settling back.
What does the refractory period do?
It stops a spike from re-firing the patch of membrane it just came from, forcing the impulse to travel in one direction only, and it sets the fastest possible firing rate of the neuron.
How does a signal cross the synapse?
The arriving spike opens Ca²⁺ channels at the presynaptic terminal, triggering vesicles to release neurotransmitter that diffuses across the cleft and binds receptors on the next neuron's membrane, creating a fresh potential change there.
What happens if myelin is damaged?
As in multiple sclerosis, damaged myelin slows and disrupts conduction, which can show up as weakness, numbness or poor coordination depending on which nerves are affected.
Does a stronger stimulus create a bigger action potential?
No — the peak stays at about +30 mV for any suprathreshold stimulus. A stronger stimulus is signalled by a higher firing rate, not a taller spike.
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